For NH4HS(s)⇌NH3(g)+H2S(g) the observed,pressure for reaction mixture in equilibrium is 1.12 atm at 1060C.
What is the value of KP for the reaction?
KP=0.04atm2
KP=0.3136atm2
KP=2.76atm2
KP=3.199,atm2
A
KP=3.199,atm2
B
KP=0.3136atm2
C
KP=0.04atm2
D
KP=2.76atm2
Open in App
Solution
Verified by Toppr
NH4HS(s)⇋NH3(g)+H2S(g)
Total pressure is 1.12 atm one half of this is equal to partial pressure of ammonia. It is also equal to partial pressure of hydrogen sulphide.
PNH3=PH2S=12×1.12=0.56 at KP=PNH3×PH2S=0.56×0.56=0.314
Thus, the value of Kp for the reaction is 0.3136 .
Was this answer helpful?
13
Similar Questions
Q1
For NH4HS(s)⇌NH3(g)+H2S(g) the observed,pressure for reaction mixture in equilibrium is 1.12 atm at 1060C.
What is the value of KP for the reaction?
View Solution
Q2
NH4HS(s)⇌NH3(G)+H2S(g) The equilibrium pressure at 25oC is 0.660atm. What is Kp for the reaction?
View Solution
Q3
For the reaction NH4HS(s)⇌NH3(g)+H2S(g), started with NH4HS(s) only. observed equilibrium pressure of the mixtures is 1.2 atm at certain temperature, what is the Kp of the reaction?
View Solution
Q4
In the equilibrium NH4HS(s)⇔NH3(g)+H2S(g) If the equilibrium pressure is 2 atm at 80∘CKp for the reaction is;
View Solution
Q5
In the equilibrium NH4HS(s)⇔NH3(g)+H2S(g). If the equilibrium pressure is 2 atm at 80o C Kp for the reaction is: