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Standard IX
Mathematics
Ratio and Proportion
Question
If
(
x
+
y
)
:
(
y
+
z
)
:
(
z
+
x
)
:
:
5
:
11
:
12
, then
x
y
=
2
3
3
2
0
1
A
2
3
B
1
C
0
D
3
2
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Solution
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Solution - Given that
(
x
+
y
)
:
(
y
+
2
)
:
(
z
+
x
)
∵
5
:
11
:
12
This can be written as
x
+
y
=
5
k
−
(
1
)
y
+
z
=
11
k
or
z
=
11
k
−
y
and
z
+
x
=
12
k
⇒
11
k
−
y
+
x
=
12
k
⇒
x
−
y
=
k
−
(
2
)
on solving (1) and (2) we get
x
=
3
k
;
y
=
2
k
∴
x
y
=
3
k
2
k
=
3
2
Hence, (A) is the correct option.
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Similar Questions
Q1
If
(
x
+
y
)
:
(
y
+
z
)
:
(
z
+
x
)
:
:
5
:
11
:
12
, then
x
y
=
View Solution
Q2
Solve the following simultaneous equations graphically.
(1) 2x + 3y = 12 ; x – y = 1
(2) x – 3y = 1 ; 3x – 2y + 4 = 0
(3) 5x – 6y + 30 = 0 ; 5x + 4y – 20 = 0
(4) 3x – y – 2 = 0 ; 2x + y = 8
(5) 3x + y = 10 ; x – y = 2