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Question

In the given figure, PA $⊥$ AB, QB $⊥$ AB and $△$ OAP $≅$ $△$ OBQ, then

PA = OB
AP = QB
OP = BQ
OA = OQ

A

OA = OQ

B

PA = OB

C

OP = BQ

D

AP = QB

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Solution

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We have given, $P A ⊥ A B$ , $Q B ⊥ A B$ and $△ O A P ≅ △ O B Q$ .
$\Rightarrow$ Therefore, by $C P C T$ we can say that,
$\Rightarrow$ $A P = Q B$

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