The fission properties of 23994Pu are very similar to those of 23592U. The average energy released per fission is 180 MeV. How much energy, in MeV, is released if all the atoms in 1 kg of pure 23994Pu undergo fission?
Number of atoms in 1 kg of pure Pu=6.023×1023239×1000=2.52×1024
As average energy released in fission is 180MeV, the total energy released is
⇒2.52×1024×180MeV
⇒4.53×1026MeV.