The formation of the oxide ion, O2−(g), from oxygen atom requires first an exothermic and then an endothermic step as shown below: O(g)+e−→O−(g);ΔfH⊖=−141kJmol−1 O−(g)+e−→O2−(g);ΔfH⊖=+780kJmol−1 Thus, process of formation of O2− in gas phase is unfavourable even though O2− is isoelectronic with neon. It is due to the fact that:
addition of electron in oxygen results in larger size of the ion
electron repulsion outweighs the stability gained by achieving noble gas configuration
O− ion has comparatively smaller size than oxygen atom
oxygen is more electronegative
A
electron repulsion outweighs the stability gained by achieving noble gas configuration
B
O− ion has comparatively smaller size than oxygen atom
C
oxygen is more electronegative
D
addition of electron in oxygen results in larger size of the ion
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The formation of the oxide ion, O2−(g), from oxygen atom requires first an exothermic and then an endothermic step as shown below:
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Q1
The formation of oxide ion, O2−(g), from oxygen atom requires first an exothermic and then an endothermic step as shown below: O(g)+e−→O−(g);ΔfH⊖=−141kJ mol−1 O−(g)+e−→O2−(g);ΔfH⊖=+780kJ mol−1 Thus the process of formation of O2− in gas phase is unfavourable even thought O2− is isoelectric with neon. It is due to the fact that,
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Q2
The formation of the oxide ion, O2−(g) from oxygen atom requires first an exothermic and then an endothermic step as shown below: O(g)+e−→O−(g);ΔfH∘=−141kJmol−1O−(g)+e−→O2−(g);ΔfH∘=+780kJmol−1 Thus, process of formation of O2− in gas phase is unfavourable even though O2− is isoelectronic with neon. It is due to the fact that,
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Q3
The formation of the oxide ion, O2−(g), from oxygen atom requires first an exothermic and then an endothermic step as shown below: O(g)+e−→O−(g);ΔfH⊖=−141kJmol−1 O−(g)+e−→O2−(g);ΔfH⊖=+780kJmol−1 Thus, process of formation of O2− in gas phase is unfavourable even though O2− is isoelectronic with neon. It is due to the fact that:
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Q4
The formation of oxide ion 0^{2-} (g) from oxygen atom requires first an exothermic and then an endothermic step as shown below O(g)+e−→O−(g);△H⊝=−141kjmol−1O−(g)+e−⇒O2(g);△H⊝=+780kjmol−1 Thus, process of formation of O2− in gas phase is unfavourable even through O2− is isoelectronic with neon. It is due to the fact that (a) Oxygen si more electronegative (b) addition of electron in oxygen results in larger size of the ion (c) electron repulsiion outweighs the stability gained by achieving noble gas configuration (d) O− ion has comparativly smaller size than oxygen atom
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Q5
The formation of the oxide ion, O2−(g), from oxygen atom requires first an exothermic and then an endothermic step as shown below: