The plates of a parallel-plate capacitor are not exactly parallel. The surface charge density, therefore,
is higher at the closer end
will not be uniform
is smallest where the plates are closet
each plate will have the same potential at each point
A
is higher at the closer end
B
each plate will have the same potential at each point
C
is smallest where the plates are closet
D
will not be uniform
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Solution
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If the plates are metallic, its a equipotential surface. So the potential will be same at each point on the plates. Since Q=CV=AϵV/d Hence, Q is inversely proportional to d. So at closer end, Q and Surface charge density would be highest.
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