A stellite of mass m is orbiting the earth (of radius R) at a height h from its surface. The total energy of the stellite in terms of g0, value of acceleration due to gravity at the earth's surface, is
−2mg0R2R+h
mg0R22(R+h)
−mg0R22(R+h)
2mg0R2R+h
A
mg0R22(R+h)
B
−2mg0R2R+h
C
−mg0R22(R+h)
D
2mg0R2R+h
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Solution
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Total energy of the satellite T=−GMm2r where r=R+h
∴T=−GMm2(R+h)
Acceleration due to gravity at earth's surface go=GMR2⟹GM=goR2
⟹T=−mgoR22(R+h)
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