A uniform bar of mass M and length L collides with a horizontal surface. Before collision, velocity of center of mass was v0 and no angular velocity. Just after collision, velocity of center of mass of bar becomes v in upward direction as shown. Angular velocity ω of the bar just after impact is :
6(v0−v)cosθL
6(v0+v)cosθL
(v0+v)cosθL
(v0−v)cosθ6L
A
6(v0−v)cosθL
B
(v0+v)cosθL
C
6(v0+v)cosθL
D
(v0−v)cosθ6L
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Solution
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Angular momentum will conserve about A just before and just after collision.
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