Bad conductor of electricity is-HClHIH-2-F-2-HBr

Question

Toppr Admin · Accepted Answer

Fluorine is the most electronegative element- So the H-F bond will be stronger than H-Cl- H-Br- H-I- Due to this H2F2 can not be ionized easily- Hence-xA0-H2F2-xA0- is a bad conductor of electricity-

Bad conductor of electricity is:
$H C l$
$H I$
$H_{2} F_{2}$
$H B r$

Fluorine is the most electronegative element. So the H-F bond will be stronger than H-Cl, H-Br, H-I. Due to this H $_{2}$ F $_{2}$ can not be ionized easily. Hence H $_{2}$ F $_{2}$ is a bad conductor of electricity.

Bad conductor of electricity is:HClHIH2F2HBr

Fluorine is the most electronegative element. So the H-F bond will be stronger than H-Cl, H-Br, H-I. Due to this H2F2 can not be ionized easily. Hence H2F2 is a bad conductor of electricity.

Bad conductor of electricity is:
$H C l$
$H I$
$H_{2} F_{2}$
$H B r$

Fluorine is the most electronegative element. So the H-F bond will be stronger than H-Cl, H-Br, H-I. Due to this H $_{2}$ F $_{2}$ can not be ionized easily. Hence H $_{2}$ F $_{2}$ is a bad conductor of electricity.