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Standard XII
Chemistry
Oxyacids of Phosphorus
Question
Equivalent weight of
H
3
P
O
4
in each of the reaction will be respectively:
H
3
P
O
4
+
O
H
−
→
H
2
P
O
−
4
+
H
2
O
H
3
P
O
4
+
2
O
H
−
→
H
P
O
2
−
4
+
2
H
2
O
H
3
P
O
4
+
3
O
H
−
→
P
O
3
−
4
+
3
H
2
O
98, 49, 32.67
49, 98, 32.67
98, 32.67, 49
32.67, 49, 98
A
49, 98, 32.67
B
98, 32.67, 49
C
32.67, 49, 98
D
98, 49, 32.67
Open in App
Solution
Verified by Toppr
E
q
u
i
v
a
l
e
n
t
w
e
i
g
h
t
=
M
o
l
e
c
u
l
a
r
w
e
i
g
h
t
N
u
m
b
e
r
o
f
E
q
u
i
v
a
l
e
n
t
s
In case of:
H
3
P
O
4
+
O
H
−
→
H
2
P
O
−
4
+
H
2
O
H
+
ions given = 1
Thus the number of equiv
=
1
E
q
u
i
v
a
l
e
n
t
w
e
i
g
h
t
=
98
1
=
98
In case of:
H
3
P
O
4
+
2
O
H
−
→
H
P
O
2
−
4
+
2
H
2
O
H
+
ions given = 2
Thus the number of equiv
=
2
E
q
u
i
v
a
l
e
n
t
w
e
i
g
h
t
=
98
2
=
49
In case of:
H
3
P
O
4
+
3
O
H
−
→
P
O
3
−
4
+
3
H
2
O
H
+
ions given = 3
Thus the number of equiv
=
3
E
q
u
i
v
a
l
e
n
t
w
e
i
g
h
t
=
98
3
=
32.67
Was this answer helpful?
12
Similar Questions
Q1
Equivalent weight of
H
3
P
O
4
in each of the reaction will be respectively:
H
3
P
O
4
+
O
H
−
→
H
2
P
O
−
4
+
H
2
O
H
3
P
O
4
+
2
O
H
−
→
H
P
O
2
−
4
+
2
H
2
O
H
3
P
O
4
+
3
O
H
−
→
P
O
3
−
4
+
3
H
2
O
View Solution
Q2
Equivalent weight of
H
3
P
O
4
in each of the reaction will be respectively:
H
3
P
O
4
+
O
H
−
→
H
2
P
O
−
4
+
H
2
O
H
3
P
O
4
+
2
O
H
−
→
H
P
O
2
−
4
+
2
H
2
O
H
3
P
O
4
+
3
O
H
−
→
P
O
3
−
4
+
3
H
2
O
View Solution
Q3
In given reactions what are the eq.weight of H
3
PO
4
?
(1)H
3
PO
4
+ OH
-
= H
2
PO
4
+ H
2
O
(2)H
3
PO
4
+ 2OH
-
= HPO
4
2-
+ H
2
O
(3)H
3
PO
4
+ 3OH
-
= PO
4
3-
+ 3H
2
O
View Solution
Q4
For
H
3
P
O
4
,
H
3
P
O
4
⇋
H
2
P
O
−
4
+
H
+
(
K
1
)
H
2
P
O
−
4
⇋
H
P
O
2
−
4
+
H
+
(
K
2
)
H
P
O
2
−
4
⇋
P
O
3
−
4
+
H
+
(
K
3
)
, then
View Solution
Q5
C
a
(
O
H
)
2
+
H
3
P
O
4
→
C
a
H
P
O
4
+
2
H
2
O
the equivalent
weight of
H
3
P
O
4
in the above reaction is
View Solution