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Standard XII
Mathematics
Existence of Limit
Question
Evaluate
lim
x
→
0
√
2
−
√
1
+
cos
x
sin
2
x
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Solution
Verified by Toppr
Solution -
lim
x
→
0
√
2
−
√
1
+
c
o
s
x
s
i
n
2
x
Apply L - Hospital Rule -
lim
x
→
0
−
1
(
−
s
i
n
x
)
2
√
1
+
c
o
s
x
2
s
i
n
x
c
o
s
x
lim
x
→
0
1
4
c
o
s
x
√
1
+
c
o
s
x
=
1
4
√
2
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