Find the magnitude of acceleration of centre of mass of two blocks as shown in figure. Neglect friction everywhere. (g = 10 ms2)
1√2 ms2
1 ms2
√2 ms2
zero
A
1 ms2
B
zero
C
√2 ms2
D
1√2 ms2
Open in App
Solution
Verified by Toppr
a=mgsin53o−mgsin37o2m=1ms−2
acm=∣∣∣m1bara1+m2¯a2m1+m2∣∣∣=a√2=1√2ms−2
Was this answer helpful?
9
Similar Questions
Q1
Find the magnitude of acceleration of centre of mass of two blocks as shown in figure. Neglect friction everywhere. (g = 10 ms2)
View Solution
Q2
A block of mass 1 kg is placed on a rough incline as shown. The coefficient of friction between block and incline is 0.4. The acceleration of block is (g=10 ms−2,√3=1.7)
View Solution
Q3
Consider two blocks of masses 5kg and 10kg as shown connected by a massless spring. A force of 100N acts on 10kg mass as shown. At a certain instant, the acceleration of 5kg mass is 12ms−2. Find the acceleration of 10kg mass.
View Solution
Q4
The system shown in the figure is released from rest with the mass 2kg in contact with the ground. The pulley and spring are massless, and friction is absent everywhere. Then, find the speed of the 5kg block when the 2kg block leaves contact with the ground (force constant of the spring k=40Nm−1 and g=10ms−2)
View Solution
Q5
A block of mass 10kg is placed on a rough horizontal surface whose coefficient of friction is 0.5. If a horizontal force of magnitude 100N is applied on the block, then acceleration of the block will be [Takeg=10ms−2]