If $$\dfrac{x+6}{3} = 7$$, what is the value of $$x$$? ( using trail and error method)
Correct option is C. $$x= 15$$
We need to find $$x$$ such that $$\dfrac{x+6}{3}$$ is $$7$$.
We know that $$\dfrac{21}{3}$$ is $$7$$.
We thus get $$7$$ if $$x+6=21$$ $$\Longrightarrow$$ $$x=15$$