If x gm of a nuclear fuel of mass number A undergoes fission inside a reactor, then the number of fission will be (N-Avogadro number)
NAx
NAx
NxA
AxN
A
NAx
B
NAx
C
NxA
D
AxN
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Power of a nuclear reactor : The output power of a nuclear reactor is given by: P=nE ----(1) Where, n= No. of fission taking place in 1 sec E= Energy released per fission. If ′x′ grams of a nuclear fuel of mass number 'A' undergo fission in a time of ′t′ sec and′E′ is energy released per fission, then the power output of the nuclear reactor is given by:
P=NExAt --(2) where N - Avagadro number. Comparing equation (1) and (2) we get:
n=NxAt Where n is no. of fission taking place in 1 sec. So, for 't' sec time, no. of fission on 't' sec will be NxAtt=NxA
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