In figure given below, AC ∥BT, m∠TOP=100∘, XY ≅ YZ, find m∠X.
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Solution
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Since AC ∥ BT so ∠ZYO=∠TOP [similar angles]
∴∠ZYO=100o⇒∠XYZ=(180o−100o)=800.
Now from ΔXYZ we get ∠ZXY=∠YZX [Since XY ≅ YZ].
Also, ∠X+∠Z=180o−80o=100o⇒∠X=50o.
∴m∠X=50o.
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In figure given below, AC ∥BT, m∠TOP=100∘, XY ≅ YZ, find m∠X.
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