Q5
Reason
Electronic configuration of oxygen atom is $$1s^{2}\ 2s^{2}\ 2p^{4}$$. The number of radial and angular nodes for an orbital is $$(n-l-1)$$ and $$l$$, respectively.
Assertion
Sum of the radial and angular nodes of all the occupied orbitals in ground state of oxygen atom is $$4$$.
Sum of the radial and angular nodes of all the occupied orbitals in ground state of oxygen atom is $$4$$.