How many unpaired electrons are present in $M n^{2 +}$ ion?

Question

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Answer 1

Atomic number of $M n$ is :

$[A r] 3 d^{5} 4 s^{2}$

Therefore the electronic configuration of $M n^{2 +}$ is : $[A r] 3 d^{5}$

As there are five 3d orbitals each orbital occupied with single electron.

Hence, there are 5 unpaired electrons in $M n^{2 +}$

Answer 2

Atomic number of

M n

is :

[A r] 3 d^{5} 4 s^{2}

Therefore the electronic configuration of

M n^{2 +}

is :

[A r] 3 d^{5}

As there are five 3d orbitals each orbital occupied with single electron.

Hence, there are 5 unpaired electrons in

M n^{2 +}