The solubility of AgI in NaI solutions is less than that in pure water because:
AgI forms complex with NaI
of common ion effect
solubility product of AgI is less than that of NaI
the temperature of the solution decreases
A
of common ion effect
B
AgI forms complex with NaI
C
solubility product of AgI is less than that of NaI
D
the temperature of the solution decreases
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Solution
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AgI⇌Ag++I− NaCl→Na++I−
Sodium iodide is a strong electrolyte and is completely dissociated. This increases the iodide ion concentration in solution and suppresses the ionization of AgI. Hence, the solubility of AgI decreases.
This is called common ion effect.
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