The solubility of CaF2 is 2×10−4 mole/litre. Its solubility product is:
2.0×10−4
4.0×10−8
8.0×8.0×10−12
3.2×10−11
A
8.0×8.0×10−12
B
3.2×10−11
C
4.0×10−8
D
2.0×10−4
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Solution
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We have
CaF2→Ca2++2F−
Kw = 4S3
Kw=4∗(2∗10−4)3
Kw= 4×8×10−12
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