The value of (5x−3y)2−(5x+3y)2, when x=−1 and y=√125 is
12
115
10
−30
A
115
B
12
C
−30
D
10
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Solution
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We know, (a−b)2−(a+b)2=(a2−2ab+b2)−(a2+2ab+b2) ⇒(a−b)2−(a+b)2=−4ab On putting a=5x and b=3y, we get ⇒(5x−3y)2−(5x+3y)2=−4(5x)(3y)=−60xy When x=−1 and y=√125=15 ⇒(5x−3y)2−(5x+3y)2=−60(−1)(15)=12
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