An electron and a proton possess the same amount of Kinetic energy. Then the relation between the wavelength of electron(λe) and the wavelength of proton(λp) is
λe=λp
λe>λp
λe<λp
λe≤λp
A
λe≤λp
B
λe>λp
C
λe=λp
D
λe<λp
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Solution
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For an electron 12mv2=E
mv=√2Em
λe=hmv
=h√2Eme
For a proton
12mv2=E
mv=√2Em
λp=h√2Emp
λeλp=√mpme λeλp>1 λe>λp
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