Electric field at center O of semicircle of radius a having linear charge density λ is given as :
2λϵoa
λπϵoa
λ2πϵoa
λπϵoa
A
2λϵoa
B
λ2πϵoa
C
λπϵoa
D
λπϵoa
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Solution
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Consider an element having charge dq at angle θ of angular width dθ Length of element =adθ dq=λadθ Field due to this element =dE=dq4πϵ0a2 →dE=λadθ4πϵ0a2=λdθ4πϵ0a
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