If velocity of a particle is three times of that of electron and ratio of de Broglie wavelength of particle to that of electron is 1.814×10−4. The particle will be :
Neutron
Deutron
Alpha
Tritium
A
Tritium
B
Neutron
C
Deutron
D
Alpha
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Solution
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The correct option is A Neutron de broglie wavelength, λ=hp ⇒λ=hmv
If velocity of a particle is three times of that of electron and ratio of de Broglie wavelength of particle to that of electron is 1.814×10−4. The particle will be :
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Q2
If velocity of a particle is 3 times that of electron and ratio of de-Broglie wavelength of the particle to that of electron is 1.8×10−4. The particle is -
Mass of electron =9.1×10−31kg
Mass of neutron =1.7×10−27kg
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Q3
A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813×10−4. The mass of the particle is (me=9.1×10−31kg)
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Q4
A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813×10−4. Calculate the particle’s mass. (Given mass of electron is 9.109×10−31kg)
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Q5
A particle is moving 5 times as fast as an electron. The ratio of the de-Broglie wavelength of the particle to that of the electron is 1.878×10−4. The mass of the particle is close to