Solve
Guides
Join / Login
Use app
Login
0
You visited us
0
times! Enjoying our articles?
Unlock Full Access!
Standard XI
Mathematics
NCERT
Question
Prove that:
sin
2
π
6
+
cos
2
π
3
−
tan
2
π
4
=
−
1
2
Open in App
Solution
Verified by Toppr
L
.
H
.
S
=
sin
2
π
6
+
cos
2
π
3
−
tan
2
π
4
=
(
1
2
)
2
+
(
1
2
)
2
−
1
2
=
−
1
2
Therefore, L.H.S
=
R.H.S
Hence proved.
Was this answer helpful?
16
Similar Questions
Q1
Prove that:
sin
2
π
6
+
cos
2
π
3
−
tan
2
π
4
=
−
1
2
View Solution
Q2
Prove that
sin
2
π
6
+
cos
2
π
3
−
tan
2
π
4
=
−
1
2
.
View Solution
Q3
Show that
i)
sin
π
6
cos
0
+
sin
π
4
cos
π
4
+
sin
π
3
cos
π
6
=
7
4
ii)
sin
2
π
6
+
cos
2
π
3
−
tan
2
π
4
=
−
1
2
View Solution
Q4
The value of
sin
2
π
6
+
cos
2
π
3
−
tan
2
π
4
+
cot
2
π
2
is equal to
View Solution
Q5
Prove that
1
−
tan
2
(
π
4
−
A
)
1
+
tan
2
(
π
4
−
A
)
=
sin
b
A
Find b
View Solution