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Standard XII
Physics
Dimensional Analysis
Question
The dimensional formula for potential energy is:
M
1
L
−
2
T
−
2
M
2
L
2
T
−
2
M
1
L
2
T
−
2
M
1
L
2
T
−
3
A
M
2
L
2
T
−
2
B
M
1
L
2
T
−
2
C
M
1
L
2
T
−
3
D
M
1
L
−
2
T
−
2
Open in App
Solution
Verified by Toppr
Potential energy
=
[
m
g
h
]
=
[
(
M
1
)
(
L
T
−
2
)
(
L
)
]
=
[
M
L
2
T
−
2
]
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7
Similar Questions
Q1
[
M
1
L
2
T
−
3
A
−
2
]
is the dimensional formula of :
View Solution
Q2
Dimensional formula of the product of the physical quantity P and Q is
[
M
1
L
2
T
−
2
]
and the dimensional formula of
P
Q
is
[
M
1
L
0
T
−
2
]
then
View Solution
Q3
Match List I with II and select the correct answer:
List-I
List-II
A.Spring constant
1.
M
1
L
2
T
−
2
B.pascal
2.
M
0
L
0
T
−
1
C.hertz
3.
M
1
L
0
T
−
2
D.joule
4.
M
1
L
−
1
T
−
2
View Solution
Q4
Match List I with List II and select the correct
answer.
List - I
List - II
A) Spring constant
I) [
M
1
L
2
T
−
2
]
B) Pascal
II) [
M
0
L
0
T
−
1
]
C) Hertz
III)[
M
1
L
0
T
−
2
]
D) Joule
IV) [
M
1
L
−
1
T
−
2
]
View Solution
Q5
If two lines with direction cosines
l
1
,
m
1
,
n
1
and
l
2
,
m
2
,
n
2
intersect,
then the angle between them would be -
View Solution