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Question

This is an example of sex-influenced genes. Fill in the appropriate genotypes at positions 1, 2, 3 and 4.
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  1. 1- BB, 2- Bb, 3- bb, 4- bb
  2. 1- Bb, 2- BB, 3- bb, 4- bb
  3. 1- BB, 2- Bb, 3- Bb , 4- bb
  4. 1- bb, 2- Bb, 3- BB, 4- Bb

A
1- bb, 2- Bb, 3- BB, 4- Bb
B
1- Bb, 2- BB, 3- bb, 4- bb
C
1- BB, 2- Bb, 3- Bb , 4- bb
D
1- BB, 2- Bb, 3- bb, 4- bb
Solution
Verified by Toppr

According to the question, baldness is a sex influenced trait. The homozygous genotypes (BB) show the trait irrespective of their sex. The heterozygous male express the trait but females with same genotype are normal. The boy at position 1 gets "B" allele from mother and other "B" allele from father, hence, its genotype is "BB (bald)". The boy at position 2 gets "b" allele from mother and "B" allele from father, hence, its genotype is "Bb (bald)". The boy at position 3 gets "b" allele from mother and other "b" allele from father, hence, its genotype is "bb (non-bald)". The girl at position 4 gets "b" allele from mother and other "b" allele from father, hence, its genotype is "bb (non-bald)". Hence, the genotypes are 1- BB, 2- Bb, 3- bb, 4- bb.
Thus, the correct answer is option A.

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Similar Questions
Q1
List IList II
A. BB×bb 1. 100% bb
B. Bb×Bb2. 25% BB, 50% Bb, 25% bb
C. BB×BB3. 100% BB
D. bb×bb4. 100% Bb
Match the genetic cross of the parents on the left with the genotypes on the right of the offspring most likely to be produced from that cross.
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Q2
The following crosses were performed between parental lines with indicated genotypes.
(i) BB×Bb
(ii) AAbb×aaBB
(iii) BB×bb
(iv) Bb×Bb
(v) AA×AA
(vi) bb×Bb
The above crosses that are expected to produce only 50% homozygotes among the F1 progeny are
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Q3
State the expected ratio of the genotypes BB and Bb in the F2 progeny.
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Q4
b - b - bb - bbb - - bb - ba
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Q5
b _ b _ bb _ bbb _ bb _ b.
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