Three charges Q,q,−q are placed at the vertices of an equilateral triangle. If the net electric potential energy of the system is 0, then Q is
−q
q
0
None of the above
A
None of the above
B
−q
C
0
D
q
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Solution
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U=UAB+UAC+UBC
⟹U=14πϵo(qQl+−qQl+−q.ql)=0
⟹q(Q−Q−q)=0
This gives both q=Q=0
And, for any vlaueQ, potential energy of this system can't be 0.
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