A body weighs W newton at the surface of the earth. Its weight at a height equal to half the radius of the earth will be:
W2
2W3
4W9
W4
A
2W3
B
4W9
C
W2
D
W4
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Solution
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At the surface
W=GMmR2......(I)
W′=GMm(3R2)2.......(II)
WW′=GMmR2GMm9R2/4
⇒WW′=94
⇒W′=4W9
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