A given charge q is situated a certain distance from a small electric dipole in the end on position experiences a force F- If the distance of the charge is doubled- the force acting on the charge will become -2FF-2F-4F-8

Question

Toppr Admin · Accepted Answer

-The electric field due-to dipole at distance r is E-x221D-1r3-Thus force on charge is-F-qE-x21D2-F-x221D-1r3-xA0-When distance is-doubled -force F-x2032-x221D-1-2r-3-F-8-

A given charge q is situated at a certain distance from a small electric dipole in the end on position experiences a force F. If the distance of the charge is doubled, the force acting on the charge will become :
$2 F$
$F / 2$
$F / 4$
$F / 8$

The electric field due to dipole at distance $r$ is $E \propto \frac{1}{r^{3}}$ .

Thus force on charge is $F = q E \Rightarrow F \propto \frac{1}{r^{3}}$

When distance is doubled ,force $F^{'} \propto \frac{1}{(2 r)^{3}} = F / 8$ .

A given charge q is situated at a certain distance from a small electric dipole in the end on position experiences a force F. If the distance of the charge is doubled, the force acting on the charge will become :2FF/2F/4F/8

The electric field due to dipole at distance r is E∝1r3. Thus force on charge is F=qE⇒F∝1r3 When distance is doubled ,force F′∝1(2r)3=F/8.

A given charge q is situated at a certain distance from a small electric dipole in the end on position experiences a force F. If the distance of the charge is doubled, the force acting on the charge will become :
$2 F$
$F / 2$
$F / 4$
$F / 8$

The electric field due to dipole at distance $r$ is $E \propto \frac{1}{r^{3}}$ .

Thus force on charge is $F = q E \Rightarrow F \propto \frac{1}{r^{3}}$

When distance is doubled ,force $F^{'} \propto \frac{1}{(2 r)^{3}} = F / 8$ .