A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is :
3Hz
1Hz
4Hz
2Hz
A
3Hz
B
1Hz
C
2Hz
D
4Hz
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Solution
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Vmax=aω⇒f=ω2π=Vmax2πa=31.42π×5=31.410π=1Hz
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