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Standard XI
Chemistry
NCERT
Question
At 450K,
K
p
=
2.0
×
10
10
/bar for the given reaction at equilibrium.
2
S
O
2
(
g
)
+
O
2
(
g
)
⇌
2
S
O
3
(
g
)
What is
K
c
at this temperature?
Open in App
Solution
Verified by Toppr
Δ
n
=
n
p
r
o
d
u
c
t
s
−
n
r
e
a
c
t
a
n
t
s
=
2
−
(
2
+
1
)
=
−
1
we know that
K
p
=
K
c
(
R
T
)
Δ
n
∴
K
c
=
K
p
(
R
T
)
−
Δ
n
=
(
2.0
×
10
10
)
×
(
0.0831
×
450
)
1
=
7.48
×
10
11
M
/
m
o
l
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Similar Questions
Q1
At 450K,
K
p
=
2.0
×
10
10
/bar for the given reaction at equilibrium.
2
S
O
2
(
g
)
+
O
2
(
g
)
⇌
2
S
O
3
(
g
)
What is
K
c
at this temperature?
View Solution
Q2
At 450 K,
K
p
= 2.0 × 10
10
/bar for the given reaction at equilibrium.
What is
K
c
at this temperature?