Energy stored in capacitor is given as: E=12CV2=1Q2V.V2(Q=CV)
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Similar Questions
Q1
Assertion :Two capacitors are connected in series with a battery. Energy stored across them is in inverse ratio of their capacity. Reason: U=12qV or U∝qV.
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Q2
In the product
→F=q(→v×→B)=q→v×(B^i+B^j+B0^k)
For q=1 and →v=2^i+4^j+6^k, →F=4^i−20^j+12^k
What will be the complete expression for →B?
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Q3
Circuit is as shown in the figure. Initially, the key is connected to 1 and now shifted to 2, before shifting of key, energy stored in capacitor is U1 and after shifting of key, energy stored in capacitor is U2, then U1U2 will be
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Q4
In the circuit shown, find the energy stored in 1μF capacitor.
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Q5
Potential difference across a capacitor of capacity 4μF is 1 kilovolt. The energy stored on capacitor is: