Find the value of a, if x=0.5 is a solution of equation ax2+(a−1)x+3=a.
24
15
10
8
A
24
B
15
C
10
D
8
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Solution
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Given equation is ax2+(a−1)x+3=a The equation can be written as ax2+(a−1)x+3−a=0 Since x=0.5 is a solution of the equation, a(0.5)2+(a−1)(0.5)+3−a=0 ⇒0.25a+0.5a−0.5+3−a=0 ⇒(0.25+0.5−1)a−0.5+3=0 ⇒−0.25a+2.5=0 ⇒0.25a=2.5 ⇒a=2.50.25 ⇒a=10
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