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Standard XII
Physics
1st Equation of Motion
Question
If a car at rest accelerates uniformly to a speed of
144
k
m
/
h
in
20
second, it covres a distance of :-
400
m
20
m
1440
m
2980
m
A
20
m
B
400
m
C
2980
m
D
1440
m
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Solution
Verified by Toppr
speed of car after 20 sec.
=
144
k
m
/
h
=
144
∗
5
18
m
/
s
=
40
m
/
s
v
=
u
+
a
t
40
=
0
+
20
a
a
=
2
m
/
s
2
Distance covered
s
=
u
t
+
1
/
2
a
t
2
=
0
∗
20
+
1
2
∗
2
∗
20
2
=
400
m
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If a car at rest accelerates uniformly to a speed of
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