The resistance between A and B in the given figure will be(in ohm):
20
30
90
more than 10 but less than 20
A
20
B
30
C
90
D
more than 10 but less than 20
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Solution
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The correct option is D more than 10 but less than 20 In the given circuit, suppose, r=10Ω r1=10Ω r2=20Ω and, r3=50Ω (Please refer the diagram.) Now, r1,r2,r3 are connected in parallel. Suppose, resultant of these three resistances is Re. Therefore, 1re=1r1+1r2+1r3=110+120+150=17100 Hence, re=10017Ω Now, resistances r and re are connected in series. Therefore, equivalent resistance in the given circuit, R=r+re R=10+10017=27017Ω, which is more than 10Ω, but less than 20Ω.
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