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Standard XII
Mathematics
Question
2
sin
2
x
+
5.2
cos
2
x
=
7
.
n
π
+
π
2
.
n
π
+
3
π
2
.
n
π
+
4
π
2
.
None of these
A
n
π
+
3
π
2
.
B
n
π
+
4
π
2
.
C
None of these
D
n
π
+
π
2
.
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Solution
Verified by Toppr
Given
2
sin
2
x
+
5.2
cos
2
x
=
7
2
(
1
−
cos
2
x
)
+
5.2
cos
2
x
=
7
2
2
(
cos
2
x
)
+
5.2
cos
2
x
=
7
Let
2
cos
2
x
=
t
cos
2
x
∈
[
0
,
1
]
2
cos
2
x
∈
[
2
0
,
2
1
]
2
cos
2
x
∈
[
1
,
2
]
⟹
2
t
+
5
t
=
7
⟹
2
+
5
t
2
=
7
t
⟹
5
t
2
−
7
t
+
2
=
0
⟹
5
t
2
−
5
t
−
2
t
+
2
=
0
⟹
5
t
(
t
−
1
)
−
2
(
t
−
1
)
=
0
⟹
t
=
2
5
,
1
But
t
∈
[
1
,
2
]
So
t
=
1
⟹
2
cos
2
x
=
2
0
⟹
cos
2
x
=
0
⟹
x
=
n
π
±
π
2
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Similar Questions
Q1
If
cot
θ
-
tan
θ
=
sec
θ
, then, θ is equal to
(a)
2
n
π
+
3
π
2
,
n
∈
Z
(b)
n
π
+
-
1
n
π
6
,
n
π
Z
(c)
n
π
+
π
2
,
n
∈
Z
(d) none of these.
View Solution
Q2
If
cot
x
-
tan
x
=
sec
x
, then, x is equal to
(a)
2
n
π
+
3
π
2
,
n
∈
Z
(b)
n
π
+
-
1
n
π
6
,
n
∈
Z
(c)
n
π
+
π
2
,
n
∈
Z
(d) none of these.
View Solution
Q3
Which of the following set of values of
x
satisfies the equation
2
2
sin
2
x
−
3
sin
x
+
1
+
2
2
−
2
sin
2
x
+
3
sin
x
=
9
(where
n
∈
Z
)
View Solution
Q4
f
(
x
)
=
tan
x
−
tan
2
x
+
tan
3
x
,
x
≠
n
π
+
π
2
View Solution
Q5
Solve the equation:
√
(
1
16
+
c
o
s
4
x
−
1
2
c
o
s
2
x
)
+
√
(
9
16
+
c
o
s
4
x
−
3
2
c
o
s
2
x
)
=
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2