A sample of radioactive material A, that has an activity of 10mCi(1Ci=3.7×1010decays/s), has twice the number of nuclei as another sample of a different radioactive maternal B which has an activity of 20mCi. The correct choices for half-life of A and B would then be respectively :
20 days and 5 days
10 days and 20 days
5 days and 10 days
10 days and 40 days
A
20 days and 5 days
B
10 days and 20 days
C
10 days and 40 days
D
5 days and 10 days
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Solution
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The correct option is A 20 days and 5 days Activity A=λN For A10=(2N0)λA For B20=N0λB ∴λB=4λA⇒(T1/2)A=4(T1/2)B
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