A spring of force constant k is cut into lengths of ratio 1:2:3. They are connected in series and the new force constant is k′. Then they are connected in parallel and force constant is k′′. Then k′:k′′ is:
1:14
1:6
1:9
1:11
A
1:14
B
1:11
C
1:6
D
1:9
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Solution
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spring in series 1k′=1k+12k+13k→k′=6k11
k"=k+2k+5k=6k k′k′′=6k116k = 111
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