An element X decays into element Z by two-step process. X⟶Y+42He Y⟶Z+2¯e then
X and Z are isobars
X and Z are isotones
X and Y are isotopes
X and Z are isotopes
A
X and Z are isotones
B
X and Z are isobars
C
X and Y are isotopes
D
X and Z are isotopes
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Solution
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Let atomic number and mass number of X be Z and A, respectively.
First step of reaction : AZX→A−4Z−2Y+42He
Second step of reaction : A−4Z−2Y→A−4ZZ+20−1e
Atoms of elements having same atomic number and different mass number are known as isotopes.
Thus X and Z are isotopes.
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