If 1st ionisation energy of Helium (He) atom is 25.6eV/atom then sum of IE1 and IE2 per atom of Helium (He) would be:
85.7eV
51.2eV
60eV
80.04eV
A
60eV
B
85.7eV
C
51.2eV
D
80.04eV
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Solution
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The first IE of He is much higher than that of its' second IE as the first e− removed is fully filled shell, i.e; 1s2.
So, IE1 of He=25.6eV
Then He+ is isoelectronic to hydrogen atom with 1s1 configuration.
△HE2=|E1(He+)|
=∣∣∣−22×13.6eV12∣∣∣
=54.44eV
∴IE1+IE2=25.6+54.4=80.04eV
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