Let the distance between the pairs of points whose cartesian coordinates are: (i) (−1,1,3),(0,5,6) be √k (ii) (2,3,−1),(2,6,2). be 3√m Find km ?
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Solution
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Let A=(−1,1,3) and B=(0,5,6) Then application of distance formula gives us AB=√12+42+32=√26=√k Hence k=26. Similarly C=(2,3,−1) and C=(2,6,2). Then CD=√02+32+32=3√2=3√m Hence m=2. Therefore km=262=13.
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