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Standard XII
Physics
Question
sec
2
θ
=
4
x
y
(
x
+
y
)
2
is true if and only if
x
+
y
≠
0
x
=
y
,
x
≠
0
x
=
y
x
≠
0
,
y
≠
0
A
x
=
y
,
x
≠
0
B
x
+
y
≠
0
C
x
=
y
D
x
≠
0
,
y
≠
0
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Solution
Verified by Toppr
sec
2
θ
≥
1
∴
4
x
y
(
x
+
y
)
2
≥
1
⇒
(
x
+
y
)
2
−
4
x
y
≤
0
⇒
(
x
−
y
)
2
≤
0
⇒
(
x
−
y
)
2
=
0
Since
(
x
−
y
)
2
can never be negative
∴
x
=
y
Here,the fraction
4
x
y
(
x
+
y
)
2
is not defined for
x
+
y
=
0
∴
x
+
y
≠
0
⇒
x
≠
0
⇒
2
x
≠
0
or
x
≠
0
Hence
x
=
y
,
x
≠
0
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25
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