The natural angular frequency of a particle of mass 'm' attached to an ideal spring of force constant 'K' is
√Km
√mK
(Km)2
(mK)2
A
√mK
B
√Km
C
(Km)2
D
(mK)2
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Solution
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Suppose you displace the particle by a distance ′x′
The spring now exerts a force,
This provides nccenary force for SHM
⇒F=mwe2x=k2 (w: natural angular frequency )
⇒w=√K/m
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