X- rays of wavelength λ falls on a photosensitive surface emitting electrons.Assuming that the work function of the surface can be neglected, prove that the de Broglie wavelength of electrons emitted will be √hλ2mc
Energy of the X-rays of wavelength=hcλ
As work function is neglected,
12mev2e=hcλ
v2e=2hcmeλ
ve=√2hcmeλ
De Brogile wavelength =hmeve
De Brogile wavelength =h√mλme√2hc
=√hλ2mec