Diameter of the circular flower bed$$=66$$m
$$\therefore$$ Radius of circular flower bed$$(r)=\dfrac{66}{2}=33$$m
$$\therefore$$ Radius of circular flower bed with $$4$$ m wide path$$(R)=33+4=37$$m
According to the question,
Area of path$$=$$Area of bigger circle$$-$$Area of smaller circle
$$=\pi R^2-\pi r^2=\pi(R^2-r^2)$$
$$=\pi[(37)^2-(33)^2]$$
$$=3.14[(37+33)(37-33)]$$ $$[\because a^2-b^2=(a+b)(a-b)]$$
$$=3.14\times 70\times 4$$
$$=879.20m^2$$.
Therefore, the area of the path is $$879.20m^2$$.