A particle executes simple harmonic motion with a frequency ′f′. The frequency with which its kinetic energy oscillates is?
f2
f
2f
4f
A
2f
B
f
C
4f
D
f2
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Solution
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Let, x=Asinωt
v=dxdt=Aωcosωt
Kinetic energy, K=12mv2
⟹K=12mω2A2cos2ωt
⟹K=12mω2A2(1+cos2ωt2)
⟹K=14mω2A2(1+cos2ωt)
∴ωK=2ω
∴ Frequency of oscillation of K.E =2f[f=ω2π]
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