A uniform rod of length l is placed symmetrically on two walls as shown in figure. The rod is in equilibrium. If N1andN2 are the normal forces exerted by the walls on the rod then:
N1>N2
N1<N2
N1andN2 would be in the vertical directions
N1=N2
A
N1andN2 would be in the vertical directions
B
N1<N2
C
N1=N2
D
N1>N2
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Solution
Verified by Toppr
As the rod is in equilibrium, thus net torque about point O is zero i.e. τo=0
∴N1×l4−N2×l4=0
⟹N1=N2
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