Compare oxygen and flourine in Ionic radiusO2−,F−:
O2−=F−
O2−<F−
O2−>F−
O2−≥F−
A
O2−>F−
B
O2−≥F−
C
O2−=F−
D
O2−<F−
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Solution
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Among the elements of same period the ion with more number of electrons and less number of protons is having more radius.If the number of electrons are same the ion with less number of protons is having more radius.
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