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Standard XII
Physics
Question
If effective length of a simple pendulum is equal to radius of earth (R), time period will be
T
=
π
√
R
g
T
=
2
π
√
2
R
g
T
=
2
π
√
R
g
T
=
2
π
√
R
2
g
A
T
=
2
π
√
2
R
g
B
T
=
π
√
R
g
C
T
=
2
π
√
R
g
D
T
=
2
π
√
R
2
g
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Solution
Verified by Toppr
formula,
T
=
2
π
√
L
R
g
(
R
+
L
)
If the effective length of a simple pendulum is equal to the radius of the earth (R),
then,
T
=
2
π
√
R
×
R
g
(
R
+
R
)
=
2
π
√
R
2
g
(
2
R
)
∴
T
=
2
π
√
R
2
g
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