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Standard XII
Physics
NCERT
Question
The half-life of a radioactive decay is
′
x
′
times its mean life. The value of
x
is
0.3010
0.6930
0.6020
1
0.6930
A
0.6930
B
0.6020
C
1
0.6930
D
0.3010
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Solution
Verified by Toppr
We have the relations:
λ
=
1
t
m
e
a
n
λ
=
l
n
2
t
h
a
l
f
Equating the two:
t
h
a
l
f
=
l
n
2
t
m
e
a
n
t
h
a
l
f
=
0.693
t
m
e
a
n
Hence,
x
=
0.693
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